函数题：枚举月份 - C/C++ 枚举与联合

定义枚举型Month，其中的枚举项以英文月份名January、February等表示；实现如下的getDays()函数；使得下述程序能正确打印指定年月的天数。

说明：函数返回指定年月的天数，getDays(2022,April)应返回30，请注意区分闰年。

### 函数接口定义：
c++
int getDays(int year, enum Month m);



### 裁判测试程序样例：
c++
#include <stdio.h>
#include <stdbool.h>

bool isLeapYear(const int year){
//四年一闰，百年不闰，四百年又闰
if (year%400==0)
return true;
else if (year%100==0)
return false;
else if (year%4==0)
return true;
else
return false;
}

//此处定义enum Month枚举类型
//此处定义getDays()函数

int main()
{
printf("Year %d, Month %d: %d days\n",1600,(int)February,getDays(1600,February));
printf("Year %d, Month %d: %d days\n",2100,(int)February,getDays(2100,February));
printf("Year %d, Month %d: %d days\n",2104,(int)February,getDays(2104,February));
printf("Year %d, Month %d: %d days\n",1997,(int)February,getDays(1997,February));
printf("Year %d, Month %d: %d days\n",1996,(int)February,getDays(1996,February));

for (int i=1;i<=12;i++){
printf("Year %d, Month %d: %d days\n",5102,(enum Month)i,getDays(5102,(enum Month)i));
}
return 0;
}


### 输入样例：
in


### 输出样例：
out
Year 1600, Month 2: 29 days
Year 2100, Month 2: 28 days
Year 2104, Month 2: 29 days
Year 1997, Month 2: 28 days
Year 1996, Month 2: 29 days
Year 5102, Month 1: 31 days
Year 5102, Month 2: 28 days
Year 5102, Month 3: 31 days
Year 5102, Month 4: 30 days
Year 5102, Month 5: 31 days
Year 5102, Month 6: 30 days
Year 5102, Month 7: 31 days
Year 5102, Month 8: 31 days
Year 5102, Month 9: 30 days
Year 5102, Month 10: 31 days
Year 5102, Month 11: 30 days
Year 5102, Month 12: 31 days


请注意：本题只需要提交相关函数及枚举类型的定义代码，不要提交完整程序。


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